1/K^2/3=60

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Solution for 1/K^2/3=60 equation: 


D( K )

K^2 = 0

K^2 = 0

K^2 = 0

1*K^2 = 0 // : 1

K^2 = 0

K = 0

K in (-oo:0) U (0:+oo)

(1/(K^2))/3 = 60 // - 60

(1/(K^2))/3-60 = 0

1/3*K^-2 = 60 // : 1/3

K^-2 = 180

-2 < 0

1/(K^2) = 180 // * K^2

1 = 180*K^2 // : 180

1/180 = K^2

K^2 = 1/180 // ^ 1/2

abs(K) = (1/180)^(1/2)

K = (1/180)^(1/2) or K = -(1/180)^(1/2)

K in { (1/180)^(1/2), -(1/180)^(1/2) }

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